Expression Add Operators

Desicription

Given a string that contains only digits 0-9 and a target value, return all possibilities to add binary operators (not unary) +, -, or * between the digits so they evaluate to the target value.

Example 1:

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Input: num = "123", target = 6
Output: ["1+2+3", "1*2*3"]

Example 2:

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Input: num = "232", target = 8
Output: ["2*3+2", "2+3*2"]

Example 3:

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Input: num = "105", target = 5
Output: ["1*0+5","10-5"]

Example 4:

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Input: num = "00", target = 0
Output: ["0+0", "0-0", "0*0"]

Example 5:

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Input: num = "3456237490", target = 9191
Output: []

Solution

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class Solution {
private:
vector<string> res{};
void dfs(int index, long cur_sum, string cur_res, char pre_op, long pre_num, const string& num, const long& target) {
if(index == num.size()) {
if(cur_sum == target) {
res.emplace_back(cur_res);
}
return ;
}
for(int i = index + 1; i <= num.size(); i++) {
string sub_str = num.substr(index, i-index);
if(to_string(stol(sub_str)).size() != sub_str.size()) {
continue;
}
dfs(i, cur_sum + stol(sub_str), cur_res + "+" + sub_str, '+', stol(sub_str), num, target);
dfs(i, cur_sum - stol(sub_str), cur_res + "-" + sub_str, '-', stol(sub_str), num, target);
dfs(i, pre_op == '-' ? cur_sum + pre_num - pre_num * stol(sub_str) : pre_op == '+' ? cur_sum - pre_num + pre_num * stol(sub_str) : pre_num * stol(sub_str), cur_res + "*" + sub_str, pre_op, pre_num * stol(sub_str), num, target);
}
}
public:
vector<string> addOperators(const string& num, long target) {
if(!num.empty()) {
for(int i = 1; i <= num.size(); i++) {
string sub_str = num.substr(0, static_cast<unsigned int>(i));
if(to_string(stol(sub_str)).size() != sub_str.size()) {
continue;
}
dfs(i, stol(sub_str), sub_str, '#', stol(sub_str), num, target);
}
}
return res;
}
};